(27)^2y-2=(3)^2y+15

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Solution for (27)^2y-2=(3)^2y+15 equation: 



(27)^2y-2=(3)^2y+15

We move all terms to the left:

(27)^2y-2-((3)^2y+15)=0

We get rid of parentheses

27^2y-3^2y-15-2=0

We add all the numbers together, and all the variables

27^2y-3^2y-17=0

We move all terms containing y to the left, all other terms to the right

27^2y-3^2y=17

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